Question

How do you solve `3(x^2) -6x + 7 = x^2 + 3x -x(x+1) + 3`?

Answer 1

`x_1=2/3` and `x_2=2`

Explanation:

`3x^2-6x+7=x^2+3x-x*(x+1)+3`

`3x^2-6x+7=x^2+3x-x^2-x+3`

`3x^2-6x+7=2x+3`

`3x^2-8x+4=0`

`(3x-2)*(x-2)=0`

Hence `x_1=2/3` and `x_2=2`