What is the period of #f(theta) = tan ( ( 13 theta)/12 )- cos ( ( 6 theta)/ 5 ) #?

1 Answer
Mar 30, 2018

#60pi#

Explanation:

Period of #tan ((13t)/12)# --> #(12(pi))/13#
Period of #cos ((6t)/5)# --> #(5(2pi))/6 = (10pi)/6 = (5pi)/3#
Period of f(t) --> least common multiple of #(12pi)/13 and (5pi)/3#
#(12pi)/13# ..x (13) = #12pi# ..x (5) --> #60pi#
#(5pi)/3# ..x(3)....... = #5pi#.x (12) --> #60pi#

Period of #f(t) = 60pi#