Question

A charge of `6 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `24 J` to `15 J`, what is the voltage between points A and B?

Answer 1

The voltage is `=1.5V`

Explanation:

Apply the equation

`"Energy"(J)"` `= " Electric potential(V)"xx"Charge (C)"`

The charge is `Q=6C`

The change in energy is `DeltaE=24-15=9J`

The voltage is

`U=(DeltaE)/(Q)=9/6=1.5V`