How do you simplify #sqrt(3y-2 ) = y#?

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Answer 1 · 2018-04-04T21:05:35

#y=1# or #y=2#

#sqrt(3y-2)=y#

#rArr 3y-2=y^2#

#rArr y^2-3y-2=0

#rArr(y-2)(y-1)=0#

#rArr y-2=0# or #y-1=0#

#rArr y=2# or #y=1#

We now check both solutions

#sqrt(3(2)-2)=2#

#sqrt(3(1)-2)=1#

So both solutions are valid.