How do you solve #28x - 16- 16x = 4( 3x - 5) + 4#?

1 Answer
larin
Apr 5, 2018

Your answer is 40. Hope it helps

Explanation:

You need to open up the bracket #4*3x=12x#, and #4*5=20#, so your equation is #2x- 16 -16x =12x - 20 + 4#, to collect like terms it will be #28x -16x -12x =20 + 4 + 16#. Dealing with the #x# side of the equation will be #28x -16x# that is equal to #12x# then #12x -12x = 0#. Now to the second part # 20 + 4 =24# and # 24 +16 =40#

Related questions
See all questions in Equations with Variables on Both Sides
Impact of this question
1706 views around the world
You can reuse this answer
Creative Commons License