How do you solve #4x - 63= 9x + 57#?

2 Answers
Apr 7, 2018

The answer is #-24#.

Explanation:

#4chi - 63 = 9chi + 57#

#4chi - 9chi = 57 + 63 #

#-5chi = 120 #

#-chi = 120/-5#

#chi = -24#

Apr 7, 2018

#x=-24#

Explanation:

#4x-63=9x+57#

We want to get #x# on one side, so we can either remove the #x# on the left side or the #x# on the right. To cancel out the #x# on the left, we need to subtract #4x# from both sides, or alternatively to cancel out the x on the left we subtract #9x# from both sides. For ease I subtracted #4x# from both sides.

#4x-63quadcolor(red)(-quad4x)=9x+57quadcolor(red)(-quad4x)#

#-63=5x+57#

Now we want to get #x# by itself, so we start by subtracting #57# from both sides:

#-63quadcolor(red)(-quad57)=5x+57quadcolor(red)(-quad57)#

#-120=5x#

Divide both sides by 5 to get x completely by itself:

#-120/color(red)5=(5x)/color(red)5#

#-24=x#

#x=-24#