How do you write #f(x) = x^2 - 4x - 10# in vertex form?
1 Answer
Apr 8, 2018
Explanation:
#"the equation of a parabola in "color(blue)"vertex form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(f(x)=a(x-h)^2+k)color(white)(2/2)|)))#
#"where "(h,k)" are the coordinates of the vertex and a is "#
#"a multiplier"#
#"to obtain this form "color(blue)"complete the square"#
#• " the coefficient of the "x^2" term must be 1 which it is"#
#• " add/subtract "(1/2"coefficient of the x-term")^2" to"#
#x^2-4x#
#rArrf(x)=x^2+2(-2)xcolor(red)(+4)color(red)(-4)-10#
#color(white)(rArrf(x))=(x-2)^2-14larrcolor(red)"in vertex form"#