How do you write #f(x) = x^2 - 4x - 10# in vertex form?

1 Answer
Apr 8, 2018

#f(x)=(x-2)^2-14#

Explanation:

#"the equation of a parabola in "color(blue)"vertex form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(f(x)=a(x-h)^2+k)color(white)(2/2)|)))#

#"where "(h,k)" are the coordinates of the vertex and a is "#
#"a multiplier"#

#"to obtain this form "color(blue)"complete the square"#

#• " the coefficient of the "x^2" term must be 1 which it is"#

#• " add/subtract "(1/2"coefficient of the x-term")^2" to"#
#x^2-4x#

#rArrf(x)=x^2+2(-2)xcolor(red)(+4)color(red)(-4)-10#

#color(white)(rArrf(x))=(x-2)^2-14larrcolor(red)"in vertex form"#