Question

How do you write `f(x)= 6x-x^2` in vertex form?

Answer 1

The general vertex form is `y = a(x-h)^2+ k` where `(h,k)` is the vertex.

Explanation:

`f(x) = 6x - x^2`
`f(x) = -x^2 + 6x - 9 + 9`
`f(x) = -(x^2 - 6x + 9) - 9`

Vertex form:
`f(x) = -(x-3)^2 - 9`

Vertex:
`(3,-9)`