How do you find the vertex and the intercepts for y = -4x^2 + 16x - 3?

1 Answer
Apr 12, 2018

Vertex is (2,13)

Explanation:

The vertex of the parabola will be the at he maximum of the

function,i.e, where dy/dx=0.

dy/dx=-8x+16=0

=>x=2
The corresponding value of y is 13

The y-intercept will be where x=0 and the x-intercept will be where y=0

So, y-intercept =-3
x-intercept is the solution of the equation

" "-4x^2+16x-3=0

which by solving we get x=0.197 and x=3.803 , these are the x-intercepts.
graph{-4x^2+16x-3 [-10.82, 21.23, -0.42, 15.6]}
All these can be checked from the graph of the function

.