Question

How do you graph `y=3tan(2x+pi/2)-2`?

Answer 1

As below.

Explanation:

Standard form of equation is `y = A tan (Bx - C) + D`

Given equation is `y = 3 tan (2x + (pi/2)) -2`

`Amplitude = |A| = " None " " for tangent"`

`"Period " = pi / |B| = pi / 2`

`"Phase Shift " = (-C) / B = (-(pi/2)) / 2 = -pi/4, " " pi/4 " to the left"`

`"Vertical Shift " = D = -2`

graph{3 tan(2x + (pi/2)) - 2 [-10, 10, -5, 5]}