What is the vertex form of #y=-4x^2-4x+1#?
2 Answers
The vertex form of equation is
Explanation:
equation
here
The vertex form of equation is
graph{-4x^2-4x+1 [-10, 10, -5, 5]}
Explanation:
#"the equation of a parabola in "color(blue)"vertex form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#
#"where "(h,k)" are the coordinates of the vertex and a "#
#"is a multiplier"#
#"using the method of "color(blue)"completing the square"#
#• " the coefficient of the "x^2" term must be 1"#
#rArry=-4(x^2+x-1/4)#
#• " add/subtract "(1/2"coefficient of the x-term")^2" to"#
#x^2+x#
#rArry=-4(x^2+2(1/2)xcolor(red)(+1/4)color(red)(-1/4)-1/4)#
#color(white)(rArry)=-4(x+1/2)^2-4(-1/4-1/4)#
#color(white)(rArry)=-4(x+1/2)^2+2larrcolor(red)"in vertex form"#