Question

A charge of `8 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `64 J` to `24 J`, what is the voltage between points A and B?

Answer 1

The voltage is `=5V`

Explanation:

Apply the equation

`"Energy"(J)"` `= " Electric potential(V)"xx"Charge (C)"`

The charge is `Q=8C`

The change in energy is `DeltaE=64-24=40J`

The voltage is

`U_(AB)=(DeltaE)/(Q)=40/8=5V`