Question

What is the vertex form of `y=x^2-8x+3`?

Answer 1

The vertex form of equation is `y= (x-4)^2-13`

Explanation:

`y= x^2-8 x+3 or y= x^2-8 x+ 16 -16 +3` or

`y= (x-4)^2-13` . Comparing with vertex form of

equation `f(x) = a(x-h)^2+k ; (h,k)` being vertex we find

here `h=4 , k= -13 :.` Vertex is at `(4, -13)` and

The vertex form of equation is `y= (x-4)^2-13`

graph{x^2-8x+3 [-40, 40, -20, 20]}