Question

How do you find the vertex of the parabola `y = (1/8)(x – 5)^2 - 3`?

Answer 1

vertex: `(5,-3)`

Explanation:

it is in vertex form, so any number with x in the parenthesis is the shift in x-axis(if x+5 -->shift 5 to left, if x-5--> shift 5 to right).
and the single number at the end of the equation is the up and down of the y-axis( -3 down 3, 3 up 3). the `(1/8)` is the stretch.

Answer 2

The vertex is `(5,-3)`.

Explanation:

`y=1/8(x-5)^2-3` is a quadratic equation in vertex form:

`y=a(x-h)^2+k`,

where:

`(h,k)` is the vertex.

`h=5`, and `k=-3`,

therefore the vertex is `(5,-3)`.