How do you find the vertex of the parabola #y = (1/8)(x – 5)^2 - 3#?

2 Answers
Apr 15, 2018

vertex: #(5,-3)#

Explanation:

it is in vertex form, so any number with x in the parenthesis is the shift in x-axis(if x+5 -->shift 5 to left, if x-5--> shift 5 to right).
and the single number at the end of the equation is the up and down of the y-axis( -3 down 3, 3 up 3). the #(1/8)# is the stretch.

Apr 15, 2018

The vertex is #(5,-3)#.

Explanation:

#y=1/8(x-5)^2-3# is a quadratic equation in vertex form:

#y=a(x-h)^2+k#,

where:

#(h,k)# is the vertex.

#h=5#, and #k=-3#,

therefore the vertex is #(5,-3)#.