How do you use Heron's formula to determine the area of a triangle with sides of that are 35, 28, and 41 units in length?

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Answer 1 · 2018-04-17T12:51:46

#483# units squared

Heron's formula states that,

#A=sqrt(s(s-a)(s-b)(s-c))#

#s# is the semiperimeter of the triangle, given by #s=(a+b+c)/2#.

#a,b,c# are the sides of the triangle

Let #a=35,b=28,c=41#

#:.s=(35+28+41)/2=104/2=52#

So, the area of this triangle will be:

#A=sqrt(52(52-35)(52-28)(52-41))#

#=sqrt(52*17*24*11)#

#=sqrt(233376)#

#~~483#

So, the area of the triangle will be #483# units squared.