If q is inversely proportional to p, and q = 3 / 2 when p = 72 how do you write the equation?
1 Answer
Apr 17, 2018
Explanation:
#"the initial statement is "qprop 1/p#
#"to convert to an equation multiply by k the constant"#
#"of variation"#
#rArrq=kxx1/p=k/p#
#"to find k use the given condition"#
#q=k/prArrk=qp=3/2xx72=108#
#"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(q=108/p)color(white)(2/2)|)))#