How do you solve #2x=7x+10#?

2 Answers
Apr 27, 2018

#x=-2#

Explanation:

#"collect terms in x on the left side of the equation"#
#"and numeric values on the right side"#

#"subtract "7x" from both sides"#

#2x-7x=cancel(7x)cancel(-7x)+10#

#rArr-5x=10#

#"divide both sides by "-5#

#(cancel(-5) x)/cancel(-5)=10/(-5)#

#rArrx=-2#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left "=2xx-2=-4#

#"right "=(7xx-2)+10=-14+10=-4#

#rArrx=-2" is the solution"#

Apr 27, 2018

#x# = -2

Explanation:

The first step to solving this equation is to place all the #x# terms on one side by subtracting #7x# from each side of the equation:

#2x - 7x = 7x - 7x + 10#
**#-5x = 10#

Now, all you need to do is divide each side by #-5# to remove the coefficient from the #x# term and get it by itself:

#(-5x)/-5 = 10/-5#
#x = -2#