How do you find the slope and intercept of 5y−4x+10=0?
2 Answers
Apr 29, 2018
Explanation:
the equation of a line in slope-intercept form is.
∙xy=mx+b
where m is the slope and b the y-intercept
rearrange 5y−4x+10=0 into this form
add 4x and subtract 10 from both sides
⇒5y=4x−10
divide all terms by 5
⇒y=45x−2←in slope-intercept form
with slope =45 and y-intercept =−2
See below:
Explanation:
The equation of the line is
So
This is in the form of
where;
y -intercept(c)=−2 - slope
(m)=45
Hope this will help you :)