Question

How do you write `y = 3(x-2)^2 + 1` in standard form?

Answer 1

`y=3x^2-12x+13`

Explanation:

`(x-2)^2 =(x-2)(x-2) = x^2-2x-2x+2=x^2-4x+4`

`3(x-2)^2=3(x^2-4x+4)=3x^2-12x+12`

So `3(x-2)^2+1 =3x^2-12x+12 +1=3x^2-12x+13`