How do you solve # 6-5(2x - 3) = 4x+7#?

2 Answers
May 3, 2018

#x=1#

Explanation:

#1# Expand:
#6-10x+15=4x+7#

#2# Simplify #6-10x+15# to #-10x+21#:
#-10x+21=4x+7#

#3# Add #10x# to both sides:
#21=4x+7+10x#

#4# Simplify #4x+7+10x# to #14x+7#:
#21=14x+7#

#5# Subtract #7# from both sides:
#21-7=14x#

#6# Simplify #21-7# to #14#
#14=14x#

#7# Divide both sides by #14#:
#1=x#

#8# Switch sides:
#x=1#

May 3, 2018

#x = 1#

Explanation:

#6-5(2x-3) = 4x + 7#

Distribute:
#6-10x + 15 = 4x + 7#

Simplify the left side:
#21 - 10x = 4x + 7#

Subtract #color(blue)7# from both sides of the equation:
#21 - 10x quadcolor(blue)(-quad7) = 4x + 7 quadcolor(blue)(-quad7)#

#14 - 10x = 4x#

Add #color(blue)(10x)# to both sides of the equation:
#14 - 10x quadcolor(blue)(+quad10x) = 4x quadcolor(blue)(+quad10x)#

#14 = 14x#

Divide both sides by #color(blue)14#:
#14/color(blue)14 = (14x)/color(blue)14#

#1 = x#

So
#x = 1#

Hope this helps!