How do you graph y>4x+2 and ?

1 Answer
May 11, 2018

graph{y>4x+2 [-10, 10, -5, 5]}

Explanation:

First, graph the line. The line is in y=mx+b form and mx is the Slope and b is the y-intercept. Since the slope is 4, the lines goes up by 4 for every x-value. Since the y-intercept is 2, it can be written as (0,2), which is the point that the line touches when the x-value is 0.
graph{y=4x+2 [-10, 10, -5, 5]}
However, we are graphing an inequality so we need to change the line to a dotted or solid one and shade either the top or the bottom. The inequality that you provided claims that y is greater than 4x+2. Since it's greater than, the top will be shaded. It doesn't say greater than or equal to so the line will be dotted. I hope this helps.
graph{y>4x+2 [-10, 10, -5, 5]}