Question

A gas originally at a temperature of 23.13C. What temperature must it be heated to triple its volume with constant pressure? Answer in celsius units

Answer 1

Recall the relationship between those parameters,

`PV = nRT`

`=>V_1/T_1 = (nR)/P = V_2/T_2`

`=> V_1/T_1 = V_2/T_2`

Generally,

`V propto T`

So we expect an increase in temperature to accompany the increase in volume. If the volume increases by a factor of three, so must the temperature.

Hence,

`3V_1 = 3T_1 = T_2 approx 69.39°"C"`

is the temperature at which this gas (all else constant) will expand to three times its original volume.