Question

How do you graph using slope and intercept of `x-3y= -13`?

Answer 1

`y=1/3x+13/3` graph{1/3x+13/3 [-20, 20, -10, 10]}

Explanation:

The slope-intercept form is `y=mx+b` therefore we have to isolate the `y`.

Begin by subtracting `x` from both sides to get `-3y=-x-13` (since `x` is positive on the left.)

Next, divide both sides by `-3` to get `y=1/3x+13/3.`

Graph by using `13/3` on the `y`- intercept and the using a rise of `1` and a run of `3` to find the next point.