Question

How do you find the slope and intercept of `(x+1)/2 + (y+1)/2 = 1`?

Answer 1

Slope: `(-1)`
y-intercept: `0`

Explanation:

Given `(x+1)/2+(y+1)/2=1`

We can multiply everything (on both sides) by `2` to get an equivalent equation:
`color(white)("XXX")(x+1)+(y+1)=2`

Simplifying:
`color(white)("XXX")x+y+2=2`

`color(white)("XXX")y=-x`

or, in slope intercept form:
`color(white)("XXX")y=color(green)(""(-1))x+color(red)0`
with slope `=color(green)(""(_1))` and y-intercept `color(red)0`