How do you solve #x - 5(x + 2) = x + 3(3 - 2x)#?

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Answer 1 · 2018-05-20T00:49:31

#x=19#

#x-5(x+2) = x +3(3-2x)#

#x-5x-10 = x +9-6x# --- use distributive property.

#-4x-10 = 9-5x# --- combine like terms

#5x-4x-10 = 9-5x +5x# --- add #5x# to both sides

#x-10 = 9#

#x-10 +10 = 9 +10# --- add #10# to both sides

#x=19#