Question

How do I use the vertex formula to determine the vertex of the graph for `y = x^2-6x+8`?

Answer 1

(3,-1)

Explanation:

use `-b/(2a)` to find the x-value
a = 1 because the first term is `x^2`
b = -6 because the second term is -6x

`-(-6)/(2*1)`

x=3

plug it back in to the original equation
`(3)^2-6(3)+8`

=-1
the vertex is (3,-1)