Question

How do you find the slope and intercept of `7x=5y`?

Answer 1

The slope is `7/5` and the y-intercept is `0`.

Explanation:

Reverse the equation.

`5y=7x`

Divide both sides by `5`.

`y=7/5x`

This equation is in slope-intercept form:

`y=mx+b`,

where `m` is the slope, and `b` is the y-intercept.

In the equation `y=7/5x`, the slope is `7/5` and the y-intercept is `0`.

graph{y=7/5x [-10, 10, -5, 5]}

Answer 2

Slope: `7/5`, Intercepts `(0,0)`

Explanation:

`7x = 5y -> y=7/5x`

Recall the equation of a straight line in slope `(m)` and `y-`intercept `(c)` form is: `y=mx+c`

In this example: `m=7/5 and c=0`

Also, `x=0` where `y=0`

Hence, `y` is a straight line through the origin with slope `7/5` as shown below.

graph{7/5x [-11.46, 11.04, -4.785, 6.465]}

So, slope of `y` is `7/5` and both `x and y` Intercepts occur at the point `(0,0)`