How do you find the slope and intercept of $7 x = 5 y$ $7x=5y$ ?

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Answer 1 · 2018-05-25T02:19:33

The slope is $\frac{7}{5}$ $7/5$ and the y-intercept is $0$ $0$ .

Reverse the equation.

$5 y = 7 x$ $5y=7x$

Divide both sides by $5$ $5$ .

$y = \frac{7}{5} x$ $y=7/5x$

This equation is in slope-intercept form:

$y = m x + b$ $y=mx+b$ ,

where $m$ $m$ is the slope, and $b$ $b$ is the y-intercept.

In the equation $y = \frac{7}{5} x$ $y=7/5x$ , the slope is $\frac{7}{5}$ $7/5$ and the y-intercept is $0$ $0$ .

graph{y=7/5x [-10, 10, -5, 5]}

Answer 2 · 2018-05-25T02:25:06

Slope: $\frac{7}{5}$ $7/5$ , Intercepts $(0, 0)$ $(0,0)$

$7 x = 5 y \to y = \frac{7}{5} x$ $7x = 5y -> y=7/5x$

Recall the equation of a straight line in slope $(m)$ $(m)$ and $y -$ $y-$ intercept $(c)$ $(c)$ form is: $y = m x + c$ $y=mx+c$

In this example: $m = \frac{7}{5} and c = 0$ $m=7/5 and c=0$

Also, $x = 0$ $x=0$ where $y = 0$ $y=0$

Hence, $y$ $y$ is a straight line through the origin with slope $\frac{7}{5}$ $7/5$ as shown below.

graph{7/5x [-11.46, 11.04, -4.785, 6.465]}

So, slope of $y$ $y$ is $\frac{7}{5}$ $7/5$ and both $x and y$ $x and y$ Intercepts occur at the point $(0, 0)$ $(0,0)$

How do you find the slope and intercept of 7x=5y7x=5y?