How do you find the area of a triangle given A=18, B=35, c=3.4?

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Answer 1 · 2018-05-25T04:08:16

#color(purple)(A_t = 3.31# sq units

#hat A = 18^@, hat B = 35^@, c = 3.4#

#hat C = (180-18-35) = 127^@#

As per Law of Sines,

#a / sin A = b / sin B = c / sin C#

#b = (c * sin B) / sin C#

#b = (3.4 * sin 35) / sin 127 = 2.44#

Area of triangle -#A_t = (1/2) b c sin A#

#A_t = (1/2) * 2.44 * 3.4 * sin (127)#

#color(purple)(A_t = 3.31# sq units

How do you find the area of a triangle given A=18*, B=35*, c=3.4?