How do you write an equation that contains points (-2, -3) and is perpendicular to 5x-2y=8?

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Answer 1 · 2018-05-27T13:36:36

#color(brown)(2x + 5y = -19#

Given equation is #5x - 2y = 8#

#y = (5/2)x - 4#

Slope of the line #m = (5/2)#

Slope of the perpendicular line #-(1/m) = -(2/5)#

Equation of line passing through (-2,-3) with slope -(2/5) is

#y + 3 = -(2/5) * (x + 2)#

#5y + 15 = -2x - 4#

#color(brown)(2x + 5y = -19#