Question

How do you convert `z=5 + 12i` to polar form?

Answer 1

`Z=13e^(i67.38^o)`

Explanation:

Polar form is represented by `Z=|quadZ|e^(itheta)`
First find modulus `|quadZ| =sqrt(5^2+12^2)=13`
and `theta = arctan(y/x) = arctan(12/5) = 67.38^o`
So answer is `Z=13e^(i67.38^o)`