How do you factor by grouping #4+9xy-18y-2x#?

Question

1561 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-30T17:28:50

#(x-2)(9y-2)#

#4+9xy-18y-2x#

group the terms like this:

#9xy-18y-2x + 4#

now factor #9y# out of the first 2 terms:

#9y(x-2)-2x + 4#

then factor #-2# out of the other 2 terms:

#9y(x-2)-2(x -2)#

Finally factor out the #(x-2)# like this:

#(x-2)(9y-2)#