Question

A charge of `12 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `60 J` to `34 J`, what is the voltage between points A and B?

Answer 1

The voltage is `=2.17V`

Explanation:

The charge is `Q=12C`

`Q=It=12C`

The Energy is

`W=UIt`

Where the voltage is `=(U)V`

The change in energy is

`DeltaW=DeltaUxxIt`

Therefore,

`DeltaU=(DeltaW)/(It)=(60-34)/12=2.17V`