What is the slope and intercept for #y + 1/2 = -1/3(x+1/2)# and how would you graph it?

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Answer 1 · 2018-06-01T12:10:59

Slope #-1/3#

Y intercept #(0,-2/3)#

expand the bracket and subtract #1/2# from both sides

#y=-1/3x-1/6-1/2#

#-1/6-1/2=-4/6=-2/3#

#y=-1/3x-2/3# this is the standard form of a straight line graph.

The gradient is #-1/3#, the y intercept is #-2/3#

When y=0, x=-2

Put x=-3 into the equation and y=#1/3#

You now have 3 points to plot

#(0,-2/3), (-2,0) and (-3,1/3)#