How do you factor $6 x - 9$ $6x-9$ ?

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Answer 1 · 2018-06-01T16:26:25

$3 (2 x - 3)$ $3(2x-3)$

To factor $6 x - 9$ $6x-9$ , begin by finding a common factor between each of the terms.

In this case $3$ $3$ goes into both $6$ $6$ and $9$ $9$

This can be factored out leaving

$3 (2 x - 3)$ $3(2x-3)$

Answer 2 · 2018-06-01T16:29:20

$x = \frac{3}{2}$ $x = 3/2$

As per the question, we have

$6 x - 9 = 0$ $6x - 9 = 0$

$:. 3(2x - 3) = 0$

$:. (2x - 3) = 0/3$

$:. 2x - 3 = 0$

$:. 2x = 3$

$:. x = 3/2$

Hence, the answer.

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