What is the vertex form of #y= (x+1)(x-12)#?

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Answer 1 · 2018-06-03T08:06:20

#y=(x-11/2)^2-85/2#

#y=(x+1)(x-12)#

Expand,

#y=x^2-11x-12#

Make a perfect square,

#y=x^2-11x+(-11/2)^2-(-11/2)^2-12#

Simplify,

#y=(x-11/2)^2-85/2#, where the vertex is #(11/2,-85/2)#

:D