How do you solve the system of equations by graphing 8x + 5y = -38x+5y=3 and -2x + y = 212x+y=21 and then classify the system?

1 Answer
Jun 4, 2018

x = -6x=6
y = 9y=9

Explanation:

8x + 5y = -38x+5y=3
-2x + y = 212x+y=21

Solving by Substitution

First, we're going to find an equation for the value of a variable to plug it into the other equation in the system. -2x + y = 212x+y=21 looks like it can easily be rearranged to get the equation for the value of yy.

-2x + y = 212x+y=21

Add 2x2x to both sides to isolate for the equation for the value of yy. You should now have:

y = 2x + 21y=2x+21

Now that you have the equation for the value of yy, you can plug the terms (2x + 21)(2x+21) into where yy would appear in the other equation of the system. So:

8x + 5y = -38x+5y=3
8x + 5(2x + 21) = -38x+5(2x+21)=3

Distribute. What this means is that you'll be multiplying 2x2x by 55 and 2121 by 55. So:

5 * 2x = 10x52x=10x
5 * 21 = 105521=105

Re-write the equation:

8x + 10x + 105 = -38x+10x+105=3
Combine like terms (10x + 8 = 18x)(10x+8=18x):

18x + 105 = -318x+105=3

This is a two-step equation. Subtract 105105 from both sides to cancel out 105105 in order to get closer to finding the value of xx.

18x = -10818x=108

Divide by 1818 to isolate for xx:

-108/18 = x10818=x

-108/18 = -610818=6

x = -6x=6

Plug the value of xx back into the equation for the value of yy to figure out yy's value:

y = 2x + 21y=2x+21
y = 2(-6) + 21y=2(6)+21
y = -12 + 21y=12+21
y = 9y=9

Plug these values back into the whole system to prove they're right:

8x + 5y = -38x+5y=3
8(-6) + 5(9) = -38(6)+5(9)=3
-48 + 45 = -348+45=3
-3 = -33=3

-2x + y = 212x+y=21
-2(-6) + 9 = 212(6)+9=21
12 + 9 = 2112+9=21
21 = 2121=21

These are the correct values.