How do you graph #y = sin(x - π/4) + 2#?

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Answer 1 · 2018-06-06T12:00:13

As below.

#y = sin (x - (pi/4)) + 2#

Standard Form of a sine function is #y = A sin (Bx - C) + D#

#:. A = 1, B = 1, C = pi/4, D = 2#

#Amplitude = |A| = 1#

Period #= (2pi) / |B| = 2pi#

Phase Shift #= -C / B = pi/4#, #pi/4# to the right#

Vertical Shift #= D = 2#

graph{sin(x-(pi/4)) + 2 [-10, 10, -5, 5]}