How do you graph #y=cot(theta+pi)#?

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Answer 1 · 2018-06-07T01:37:27

As Below

#color(indigo)(y = A cot (B theta - C) + D#

Given function is #y cot (theta + pi)#

#Amplitude = |A| = color(red)("None") for cotangent function

#"Period " = pi / |B| = pi#

#"Phase Shift " = - C/B = -pi, color(indigo)(pi) " to the left"#

#"vertical Shift " = D = 0#

graph{cot (x + pi) [-10, 10, -5, 5]}