How do you graph $y=4csc3(x-pi)$ ?

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Answer 1 · 2018-06-07T02:02:45

As below.

$y = 4 csc (3x - 3pi)$

Standard form $color(crimson)(y = A csc (Bx - C) + D$

$Amplitude = |A| = color(green("NONE") " for Tangent"$

$"Period " = (2pi) / |B| = (2pi) / 3$

$"Phase Shift " = -C / B = pi / 3$

$"Vertical Shift " = D = 0$

graph{4 csc (3x - 3pi) [-10, 10, -5, 5]}

How do you graph y=4csc3(x-pi)y=4csc3(x-pi)?