How do you write an equation in slope-intercept form for a line that is parallel to the given line y = -1/4x + 9 and passes through the given point(-4, 4)?

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Answer 1 · 2018-06-13T08:02:18

#y = -1/4x +3#

Since the line

#y = -1/4x+9#

is already in slope-intercept form, we know that the slope of the line is #-1/4#.

Two lines are parallel if they have the same slope, so our line will also have slope #-1/4#, which means that it has equation like

#y = -1/4x+q#

Let's impose the passage through #(-4,4)#:

#4 = -1/4*(-4)+q \iff 4 = 1+q \iff q=3#

So, the equation is

#y = -1/4x +3#