Question

How do you write an equation of the line with slope=5 passing through point (-8,2) in standard form?

Answer 1

`5x-y=-42`

Explanation:

use point slope form first, because you are given a point and a slope:
`y-y_1=m(x-x_1)`
which is:
`y-2=5(x+8)`
Then convert to slope intercept form by distributing the 5 and adding over the 2:
`y=5x+42`
Then subtract the y and 42 to the opposite sides to convert it to standard form:
`5x-y=-42`