How do you write an equation of the line with slope=5 passing through point (-8,2) in standard form?

1 Answer
Jun 13, 2018

5x-y=-42

Explanation:

use point slope form first, because you are given a point and a slope:
y-y_1=m(x-x_1)
which is:
y-2=5(x+8)
Then convert to slope intercept form by distributing the 5 and adding over the 2:
y=5x+42
Then subtract the y and 42 to the opposite sides to convert it to standard form:
5x-y=-42