How do you graph $y = - 2 + 3 cos (x - π)$ $y=-2+3cos(x-pi)$ ?

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Answer 1 · 2018-06-18T01:35:16

As below.

Standard form of cosine function is $y = A cos (B x - C) + D$ $y = A cos (Bx - C) + D$

$Given : y = 3 cos (x - π) - 2$ $"Given : " y = 3 cos (x - pi) - 2$

$A = 3, B = 1, C = π, D = - 2$ $A = 3, B = 1, C = pi, D = -2$

$Amplitude = | A | = 3$ $"Amplitude " = |A| = 3$

$Period = \frac{2 π}{| B |} = \frac{2 π}{1} = 2 π$ $"Period " = (2pi) / |B| = (2pi) / 1 = 2pi$

$Phase Shift = - \frac{C}{B} = - \frac{π}{1} = - π, π to the LEFT$ $"Phase Shift " = -C / B = -pi / 1 = -pi, pi " to the LEFT"$

$Vertical Shift = D = - 2$ $"Vertical Shift " = D = -2$

graph{3 cos (x - pi) - 2 [-10, 10, -5, 5]}

How do you graph y=−2+3cos(x−π)y=-2+3cos(x-pi)?