How do you write an equation of a line with slope 5/2 and y-intercept 0?

2 Answers
Jun 23, 2018

See a solution process below:

Explanation:

We can use the slope-intercept formula to write an equation for this line. The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

Substituting:

#color(red)(5/2)# for #color(red)(m)#

And

#color(blue)(0)# for #color(blue)(b)#

Gives:

#y = color(red)(5/2)x + color(blue)(0)#

Or

#y = color(red)(5/2)x#

Jun 23, 2018

#y=5/2x#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"here "m=5/2" and "b=0#

#y=5/2xlarrcolor(red)"is the equation of the line"#