Question

How do you solve `2x^2+x<15`?

Answer 1

`-3 < x <2.5`

Explanation:

We can re-arrange and say:

`2x^2+x-15<0`

By factorising:

`(2x-5)(x+3)<0`

`therefore` `2x-5<0`

`rArr 2x<5`

`rArr x<2.5`

`x+3<0`

`rArr x<-3`

Therefore:

`therefore` `-3 < x <2.5`