Question

What is the vertex form of `y=-2x^2+2x-2`?

Answer 1

`y=-2(x^2-1/2)^2-3/2`

Explanation:

Complete the square:
`y=-2x^2+2x-2`
`y=-2(x^2-x)-2`
`y=-2(x^2-x+1/4-1/4)-2`
`y=-2(x^2-1/2)^2+1/2-2`
`y=-2(x^2-1/2)^2-3/2`

...which is the equation in vertex form.