A charge of #5 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #22 J# to #19 J#, what is the voltage between points A and B?

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Answer 1 · 2018-07-13T09:07:36

The voltage is #=0.6V#

The charge is

#Q=It=5C#

The Energy is

#W=UIt=UQ#

The change in the energy is

#DeltaW=QDeltaU#

Therefore,

#DeltaU=(DeltaW)/Q=(22-19)/5=0.6V#