How do you graph $y=cot(x/3+240)$ ?

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Answer 1 · 2018-07-14T12:55:45

See graph and explanation.

The plot is for y against x in radian.

If it is $240^o = (4/3)pi$ radian, the befitting equation is

$y = cot ( 1/3(x+4pi))$
The period = $pi/(1/3) = 3pi = 9.425$ , nearly.

The Socratic graph is immediate.
graph{y -cot (1/3(x+4pi)) = 0[-25 20 -10 10]}

How do you graph y=cot(x/3+240)y=cot(x/3+240)?