How do you solve the system by graphing #3x + y = 3# and #x - 4y = 1#?

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Answer 1 · 2018-07-25T17:05:25

#x=1, \ \y=0#

Given equations

#3x+y=3\ .......(1)#

#x-4y=1\ ......(2)#

Multiplying (2) by #3# & subtracting from (1) as follows

#3x+y-3(x-4y)=3-3\cdot 1#

#13y=0#

#y=0#

setting #y=0# in (1), we get

#3x+0=3#

#x=1#