Question

How do you graph `y=csc(pi-x)` and include two full periods?

Answer 1

See graph and details.

Explanation:

`y = csc (pi - x ) = 1/sin ( pi - x ) = 1/sin x notin ( - 1, 1 )`

And, asymptotic x = any zero of the denominator `sin x`

`= kpi, k = 0, +-1, +-2, +-3, ...`

The period = period of `sin x = 2 pi`.

Graph for two periods,

`x in ( - 2 pi, 2 pi )`, with asymptotes `x = +- pi` and

y not-to-be-in `( -1, 1 )`:
graph{(y sin x - 1)(y^2-1)(x)(x^2-(pi)^2)(x^2-4(pi)^2)=0[-10 10 -5 5]}