Alternating Series Test (Leibniz's Theorem) for Convergence of an Infinite Series

Key Questions

  • In most cases, an alternation series #sum_{n=0}^infty(-1)^nb_n# fails Alternating Series Test by violating #lim_{n to infty}b_n=0#. If that is the case, you may conclude that the series diverges by Divergence (Nth Term) Test.

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  • Alternating Series Test

    An alternating series #sum_{n=1}^infty(-1)^n b_n#, #b_n ge 0# converges if both of the following conditions hold.

    #{(b_n ge b_{n+1} " for all " n ge N),(lim_{n to infty}b_n=0):}#


    Let us look at the posted alternating series.

    In this series, #b_n=1/sqrt{3n+1}#.

    #b_n=1/sqrt{3n+1} ge 1/sqrt{3(n+1)+1}=b_{n+1}# for all #n ge 1#.

    and

    #lim_{n to infty}b_n=lim_{n to infty}1/sqrt{3n+1}=1/infty=0#

    Hence, we conclude that the series converges by Alternating Series Test.


    I hope that this was helpful.

  • Alternating Series Test states that an alternating series of the form
    #sum_{n=1}^infty (-1)^nb_n#, where #b_n ge0#,
    converges if the following two conditions are satisfied:
    1. #b_n ge b_{n+1}# for all #n ge N#, where #N# is some natural number.
    2. #lim_{n to infty}b_n=0#

    Let us look at the alternating harmonic series #sum_{n=1}^infty (-1)^{n-1}1/n#.
    In this series, #b_n=1/n#. Let us check the two conditions.
    1. #1/n ge 1/{n+1}# for all #n ge 1#
    2. #lim_{n to infty}1/n=0#

    Hence, we conclude that the alternating harmonic series converges.

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